What is the derivative of x^4-5x^3 ?

The derivative of x^4-5x^3 is 4x^3-15x^2

What is the first derivative of x^4-5x^3 ?

The first derivative of x^4-5x^3 is 4x^3-15x^2

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\frac{d}{d x} (x^{4} - 5 x^{3})

4 x^{3} - 15 x^{2}

Solution steps

\frac{d}{d x} (x^{4} - 5 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (5 x^{3})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

= 4 x^{3} - 15 x^{2}

\frac{d}{d x} (\frac{x + 10}{x - 10})

\int x 1 + x d x

ln (8 x + 5)

x y^{^{'}} + 9 y = 12 y^{2}, y (1) = - 1

\frac{d}{d x} (x \cdot a)

What is the derivative of x^4-5x^3 ?
The derivative of x^4-5x^3 is 4x^3-15x^2
What is the first derivative of x^4-5x^3 ?
The first derivative of x^4-5x^3 is 4x^3-15x^2