What is the integral from 0 to 7 of 9800pi(7-y) ?

The integral from 0 to 7 of 9800pi(7-y) is 240100pi

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integral from 0 to 7 of 9800pi(7-y)

\int_{0}^{7} 9800 π (7 - y) d y

240100 π

Decimal Notation

754296.39612 \dots

Solution steps

\int_{0}^{7} 9800 π (7 - y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9800 π \cdot \int_{0}^{7} 7 - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 9800 π (\int_{0}^{7} 7 d y - \int_{0}^{7} y d y)

\int_{0}^{7} 7 d y = 49

\int_{0}^{7} y d y = \frac{49}{2}

= 9800 π (49 - \frac{49}{2})

Simplify

9800 π (49 - \frac{49}{2}) : 240100 π

= 240100 π

y = \frac{1}{( 1 + x ^{2} ) , ( - 1 , \frac{1}{2} )}

\int (x e^{2 x}) d x

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} + 5 y = 0

\int \frac{x ^{2} + 18 x - 9}{x ^{3} - 9 x} d x

y = x (x + 1)^{2}, y = 0

What is the integral from 0 to 7 of 9800pi(7-y) ?
The integral from 0 to 7 of 9800pi(7-y) is 240100pi