What is the integral of (xe^{2x}) ?

The integral of (xe^{2x}) is 1/4 (e^{2x}*2x-e^{2x})+C

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integral of (xe^{2x})

\int (x e^{2 x}) d x

\frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x}) + C

Solution steps

\int x e^{2 x} d x

Apply u-substitution

: \int \frac{e ^{u} u}{4} d u

= \int \frac{e ^{u} u}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int e^{u} u d u

Apply Integration By Parts

: e^{u} u - \int e^{u} d u

= \frac{1}{4} (e^{u} u - \int e^{u} d u)

\int e^{u} d u = e^{u}

= \frac{1}{4} (e^{u} u - e^{u})

Substitute back

u = 2 x

= \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x})

Add a constant to the solution

= \frac{1}{4} (e^{2 x} \cdot 2 x - e^{2 x}) + C

\frac{d ^{2} y}{d x ^{2}} + 6 \frac{d y}{d x} + 5 y = 0

\int \frac{x ^{2} + 18 x - 9}{x ^{3} - 9 x} d x

y = x (x + 1)^{2}, y = 0

\int_{0}^{\frac{π}{12}} cos (4 x) d x

f (x) = sin^{3} (18 x)

What is the integral of (xe^{2x}) ?
The integral of (xe^{2x}) is 1/4 (e^{2x}*2x-e^{2x})+C