What is (\partial)/(\partial z)(4sin^2(z)) ?

The answer to (\partial)/(\partial z)(4sin^2(z)) is 4sin(2z)

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(\partial)/(\partial z)(4sin^2(z))

\frac{\partial}{\partial z} (4 sin^{2} (z))

4 sin (2 z)

Solution steps

\frac{\partial}{\partial z} (4 sin^{2} (z))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{\partial}{\partial z} (sin^{2} (z))

Apply the chain rule:

2 sin (z) \frac{\partial}{\partial z} (sin (z))

= 2 sin (z) \frac{\partial}{\partial z} (sin (z))

\frac{\partial}{\partial z} (sin (z)) = cos (z)

= 4 \cdot 2 sin (z) cos (z)

Simplify

4 \cdot 2 sin (z) cos (z) : 4 sin (2 z)

= 4 sin (2 z)

\int (x - \frac{1}{x}) d x

\frac{d}{d x} (e^{2^{x}})

d x + e^{- 5 x} d y = 0

f (x) = 2 ln (6 + x)

\frac{d}{d x} (\frac{3}{lo g _{8} ( x )})

What is (\partial)/(\partial z)(4sin^2(z)) ?
The answer to (\partial)/(\partial z)(4sin^2(z)) is 4sin(2z)