What is (\partial)/(\partial x)(9x^7cos(y^4)) ?

The answer to (\partial)/(\partial x)(9x^7cos(y^4)) is 63x^6cos(y^4)

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(\partial)/(\partial x)(9x^7cos(y^4))

\frac{\partial}{\partial x} (9 x^{7} cos (y^{4}))

63 x^{6} cos (y^{4})

Solution steps

\frac{\partial}{\partial x} (9 x^{7} cos (y^{4}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 cos (y^{4}) \frac{\partial}{\partial x} (x^{7})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 cos (y^{4}) \cdot 7 x^{7 - 1}

Simplify

= 63 x^{6} cos (y^{4})

f (x) = ln (64 sin^{2} (x))

y^{^{''}} - 3 y^{^{'}} - 4 y = e^{3 t}

y = \frac{x ^{3}}{2} + \frac{x ^{2}}{2} - 2 x, y = \frac{x ^{2}}{2}

f (x) = cos^{2} (3 x + 1)

\frac{d}{d x} (ln (4 + x^{2}))

What is (\partial)/(\partial x)(9x^7cos(y^4)) ?
The answer to (\partial)/(\partial x)(9x^7cos(y^4)) is 63x^6cos(y^4)