What is the integral of (e^{-t})/(t^2) ?

The integral of (e^{-t})/(t^2) is -(e^{-t})/t-\Ei(-t)+C

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integral of (e^{-t})/(t^2)

\int \frac{e ^{- t}}{t ^{2}} d t

- \frac{e ^{- t}}{t} - Ei (- t) + C

Solution steps

\int \frac{e ^{- t}}{t ^{2}} d t

Apply Integration By Parts

: - \frac{e ^{- t}}{t} - \int \frac{e ^{- t}}{t} d t

= - \frac{e ^{- t}}{t} - \int \frac{e ^{- t}}{t} d t

\int \frac{e ^{- t}}{t} d t = Ei (- t)

= - \frac{e ^{- t}}{t} - Ei (- t)

Add a constant to the solution

= - \frac{e ^{- t}}{t} - Ei (- t) + C

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What is the integral of (e^{-t})/(t^2) ?
The integral of (e^{-t})/(t^2) is -(e^{-t})/t-\Ei(-t)+C