What is the integral from-1 to 3 of 1/5 x^3 ?

The integral from-1 to 3 of 1/5 x^3 is 4

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integral from-1 to 3 of 1/5 x^3

\int_{- 1}^{3} \frac{1}{5} x^{3} d x

4

Solution steps

\int_{- 1}^{3} \frac{1}{5} x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int_{- 1}^{3} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 1}^{3}

= \frac{1}{5} [\frac{x ^{4}}{4}]_{- 1}^{3}

Compute the boundaries:

20

= \frac{1}{5} \cdot 20

Simplify

= 4

f (x) = 3 arcsin (x), at x = \frac{1}{2}

\frac{d}{d x} (a csc (2) (k x))

\int 5 sec^{4} (x) d x

\frac{d}{d x} (r e^{r x})

\frac{d}{d x} (4 (5 - 7 x)^{5})

What is the integral from-1 to 3 of 1/5 x^3 ?
The integral from-1 to 3 of 1/5 x^3 is 4