What is the integral of e^{-7x^2} ?

The integral of e^{-7x^2} is (sqrt(pi))/(2sqrt(7))\erf(sqrt(7)x)+C

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integral of e^{-7x^2}

\int e^{- 7 x^{2}} d x

\frac{π}{2 7} erf (7 x) + C

Solution steps

\int e^{- 7 x^{2}} d x

= \int e^{- (7 x)^{2}} d x

Apply u-substitution

: \int e^{- u^{2}} \frac{1}{7} d u

= \int e^{- u^{2}} \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int e^{- u^{2}} d u

Use the nonelementary integral:

\int e^{- u^{2}} d u = \frac{π}{2} erf (u)

= \frac{1}{7} \cdot \frac{π}{2} erf (u)

Substitute back

u = 7 x

= \frac{1}{7} \cdot \frac{π}{2} erf (7 x)

Simplify

\frac{1}{7} \cdot \frac{π}{2} erf (7 x) : \frac{π}{2 7} erf (7 x)

= \frac{π}{2 7} erf (7 x)

Add a constant to the solution

= \frac{π}{2 7} erf (7 x) + C

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What is the integral of e^{-7x^2} ?
The integral of e^{-7x^2} is (sqrt(pi))/(2sqrt(7))\erf(sqrt(7)x)+C