What is the integral from-infinity to-2 of xe^x ?

The integral from-infinity to-2 of xe^x is -3/(e^2)

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integral from-infinity to-2 of xe^x

\int_{- \infty}^{- 2} x e^{x} d x

- \frac{3}{e ^{2}}

Solution steps

\int_{- \infty}^{- 2} x e^{x} d x

Compute the indefinite integral:

\int x e^{x} d x = e^{x} x - e^{x} + C

Compute the boundaries:

\int_{- \infty}^{- 2} x e^{x} d x = - \frac{3}{e ^{2}} - 0

= - \frac{3}{e ^{2}} - 0

Simplify

= - \frac{3}{e ^{2}}

\int_{0}^{4} \frac{3}{64} x^{2} d x

\frac{1}{4} y^{^{''}} + 4 y = 2 tan (4 t)

x \to 6 - lim (ln (x - 6))

sin (1 + x^{2})

\frac{d}{d x} (sec^{3} (4 x))

What is the integral from-infinity to-2 of xe^x ?
The integral from-infinity to-2 of xe^x is -3/(e^2)