What is the integral from-4 to 3 of 1/(x^3) ?

The integral from-4 to 3 of 1/(x^3) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-4 to 3 of 1/(x^3)

\int_{- 4}^{3} \frac{1}{x ^{3}} d x

diverges

Solution steps

\int_{- 4}^{3} \frac{1}{x ^{3}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 4}^{0} \frac{1}{x ^{3}} d x + \int_{0}^{3} \frac{1}{x ^{3}} d x

\int_{- 4}^{0} \frac{1}{x ^{3}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{1} (x^{2} + 6) e^{5 x} d x

\int_{0}^{1} (2 x + 1) d x

\int_{1}^{\infty} \frac{1}{1 + x} d x

\int_{1}^{4} \frac{x - 5}{x} d x

\int_{0}^{1 - x} 6 (1 - x - y) d y

What is the integral from-4 to 3 of 1/(x^3) ?
The integral from-4 to 3 of 1/(x^3) is diverges