What is the integral from 1 to infinity of 1/(1+x) ?

The integral from 1 to infinity of 1/(1+x) is diverges

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integral from 1 to infinity of 1/(1+x)

\int_{1}^{\infty} \frac{1}{1 + x} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{1 + x} d x

Compute the indefinite integral:

\int \frac{1}{1 + x} d x = ln ∣ 1 + x ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{1 + x} d x =

diverges

= diverges

\int_{1}^{4} \frac{x - 5}{x} d x

\int_{0}^{1 - x} 6 (1 - x - y) d y

\int_{0}^{4} (1 - e^{- 2 x}) d x

\int_{1}^{6} \frac{1}{x ^{2}} d x

\int_{- 1}^{0} x + 1 d x

What is the integral from 1 to infinity of 1/(1+x) ?
The integral from 1 to infinity of 1/(1+x) is diverges