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Popular >

integral from 0 to 1 of (2x+1)

Solution

\int_{0}^{1} (2 x + 1) d x

Solution

2

Solution steps

\int_{0}^{1} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 2 x d x = 1

\int_{0}^{1} 1 d x = 1

= 1 + 1

Simplify

= 2

Popular Examples

integral from 1 to infinity of 1/(1+x)

\int_{1}^{\infty} \frac{1}{1 + x} d x

integral from 1 to 4 of (x-5)/(sqrt(x))

\int_{1}^{4} \frac{x - 5}{x} d x

integral from 0 to 1-x of 6(1-x-y)

\int_{0}^{1 - x} 6 (1 - x - y) d y

integral from 0 to 4 of (1-e^{-2x})

\int_{0}^{4} (1 - e^{- 2 x}) d x

integral from 1 to 6 of 1/(x^2)

\int_{1}^{6} \frac{1}{x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (2x+1) ?
The integral from 0 to 1 of (2x+1) is 2