What is the integral from 2 to 3 of e^tcos(e^t) ?

The integral from 2 to 3 of e^tcos(e^t) is sin(e^3)-sin(e^2)

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integral from 2 to 3 of e^tcos(e^t)

\int_{2}^{3} e^{t} cos (e^{t}) d t

sin (e^{3}) - sin (e^{2})

Decimal Notation

0.05061 \dots

Solution steps

\int_{2}^{3} e^{t} cos (e^{t}) d t

Apply u-substitution

: \int_{e^{2}}^{e^{3}} cos (u) d u

= \int_{e^{2}}^{e^{3}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= [sin (u)]_{e^{2}}^{e^{3}}

Compute the boundaries:

sin (e^{3}) - sin (e^{2})

= sin (e^{3}) - sin (e^{2})

\int_{1}^{2} tan (x) y d y

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\int_{- 1}^{4} \frac{2}{3 x ^{2}} d x

\int_{1}^{- 1} (12 r + 11)^{2} d r

\int_{- 1}^{0} \frac{1}{x ^{2} - 4} d x

What is the integral from 2 to 3 of e^tcos(e^t) ?
The integral from 2 to 3 of e^tcos(e^t) is sin(e^3)-sin(e^2)