What is the integral from-4 to 6 of 1/(sqrt(6-x)) ?

The integral from-4 to 6 of 1/(sqrt(6-x)) is 2sqrt(10)

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integral from-4 to 6 of 1/(sqrt(6-x))

\int_{- 4}^{6} \frac{1}{6 - x} d x

210

Decimal Notation

6.32455 \dots

Solution steps

\int_{- 4}^{6} \frac{1}{6 - x} d x

Apply u-substitution

: \int_{10}^{0} - \frac{1}{u} d u

= \int_{10}^{0} - \frac{1}{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{10} - \frac{1}{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{0}^{10} \frac{1}{u} d u)

Apply the Power Rule

: [2 u^{\frac{1}{2}}]_{0}^{10}

= - (- [2 u^{\frac{1}{2}}]_{0}^{10})

Simplify

- (- [2 u^{\frac{1}{2}}]_{0}^{10}) : [2 u]_{0}^{10}

= [2 u]_{0}^{10}

Compute the boundaries:

210

= 210

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What is the integral from-4 to 6 of 1/(sqrt(6-x)) ?
The integral from-4 to 6 of 1/(sqrt(6-x)) is 2sqrt(10)