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Popular >

integral from-1 to 1 of (|x|-1)

Solution

\int_{- 1}^{1} (∣ x ∣ - 1) d x

Solution

- 1

Solution steps

\int_{- 1}^{1} ∣ x ∣ - 1 d x

Eliminate Absolutes

= \int_{- 1}^{0} - x - 1 d x + \int_{0}^{1} x - 1 d x

\int_{- 1}^{0} - x - 1 d x = - \frac{1}{2}

\int_{0}^{1} x - 1 d x = - \frac{1}{2}

= - \frac{1}{2} - \frac{1}{2}

Simplify

- \frac{1}{2} - \frac{1}{2} : - 1

= - 1

Popular Examples

integral from 3 to 4 of x^2-2x-3

\int_{3}^{4} x^{2} - 2 x - 3 d x

integral from 0 to pi/2 of 1/(1+cos(x))

\int_{0}^{\frac{π}{2}} \frac{1}{1 + cos ( x )} d x

integral from-1 to 2 of 3x

\int_{- 1}^{2} 3 x d x

integral from 0 to 2 of (x^2)/4

\int_{0}^{2} \frac{x ^{2}}{4} d x

integral from 0 to 4 of x^3-6x^2+8x

\int_{0}^{4} x^{3} - 6 x^{2} + 8 x d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (|x|-1) ?
The integral from-1 to 1 of (|x|-1) is -1