What is the integral from-1 to 2 of 1/(sqrt(x+2)) ?

The integral from-1 to 2 of 1/(sqrt(x+2)) is 2

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integral from-1 to 2 of 1/(sqrt(x+2))

\int_{- 1}^{2} \frac{1}{x + 2} d x

2

Solution steps

\int_{- 1}^{2} \frac{1}{x + 2} d x

Apply u-substitution

: \int_{1}^{2} 2 d u

= \int_{1}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{1}^{2}

Compute the boundaries:

2

= 2

\int_{0}^{4} x^{2} - 2 x d x

\int_{0}^{0.8} e^{- x^{2}} d x

\int_{- 2}^{- 1} x^{2} - 1 d x

\int_{- 1}^{4} x^{2} - 4 x d x

\int_{0}^{4} 5 (1 - e^{y}) d y

What is the integral from-1 to 2 of 1/(sqrt(x+2)) ?
The integral from-1 to 2 of 1/(sqrt(x+2)) is 2