What is the integral from 2 to 5 of 4^{5x} ?

The integral from 2 to 5 of 4^{5x} is (2^{49}-524288)/(5ln(2))

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integral from 2 to 5 of 4^{5x}

\int_{2}^{5} 4^{5 x} d x

\frac{2 ^{49} - 524288}{5 ln ( 2 )}

Solution steps

\int_{2}^{5} 4^{5 x} d x

Simplify

4^{5 x} : 102 4^{x}

= \int_{2}^{5} 102 4^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{102 4 ^{x}}{ln ( 1024 )}]_{2}^{5}

\frac{102 4 ^{x}}{ln ( 1024 )} = \frac{2 ^{10 x - 1}}{5 ln ( 2 )}

= [\frac{2 ^{10 x - 1}}{5 ln ( 2 )}]_{2}^{5}

Compute the boundaries:

\frac{2 ^{49} - 524288}{5 ln ( 2 )}

= \frac{2 ^{49} - 524288}{5 ln ( 2 )}

\int_{0}^{2} (3 x + 1) d x

\int_{8}^{9} 1 d t

\int_{2}^{4} \frac{x}{( x ^{2} + 5 ) ^{3}} d x

\int_{3}^{4} x^{2} + x - 5 d x

\int_{0}^{r} r d r

What is the integral from 2 to 5 of 4^{5x} ?
The integral from 2 to 5 of 4^{5x} is (2^{49}-524288)/(5ln(2))