en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of (2-2x^2)

Solution

\int_{- 1}^{1} (2 - 2 x^{2}) d x

Solution

\frac{8}{3}

+1

Solution steps

\int_{- 1}^{1} 2 - 2 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 d x - \int_{- 1}^{1} 2 x^{2} d x

\int_{- 1}^{1} 2 d x = 4

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

= 4 - \frac{4}{3}

Simplify

4 - \frac{4}{3} : \frac{8}{3}

= \frac{8}{3}

Popular Examples

integral from 1 to 2 of 2^x

\int_{1}^{2} 2^{x} d x

integral from 1 to 4 of 2x-x^2

\int_{1}^{4} 2 x - x^{2} d x

integral from 0 to 2 of t/(sqrt(5+t^2))

\int_{0}^{2} \frac{t}{5 + t ^{2}} d t

integral from 1 to e of ln(\sqrt[x]{x})

integral from 0 to pi/4 of sin(2x+pi/2)

\int_{0}^{\frac{π}{4}} sin (2 x + \frac{π}{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (2-2x^2) ?
The integral from-1 to 1 of (2-2x^2) is 8/3