What is the integral from 0 to pi/3 of (sin(x)) ?

The integral from 0 to pi/3 of (sin(x)) is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/3 of (sin(x))

\int_{0}^{\frac{π}{3}} (sin (x)) d x

\frac{1}{2}

Solution steps

\int_{0}^{\frac{π}{3}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{π}{3}}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int_{0}^{1} sin (y^{2}) d y

\int_{0}^{π} 2 x cos (n x) d x

\int_{0}^{9} 2 x d x

\int_{0}^{4} (6 x^{3} - 3 x) d x

\int_{1}^{2} 5^{4 x} d x

What is the integral from 0 to pi/3 of (sin(x)) ?
The integral from 0 to pi/3 of (sin(x)) is 1/2