What is the integral from 0 to 4 of (6x^3-3x) ?

The integral from 0 to 4 of (6x^3-3x) is 360

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of (6x^3-3x)

\int_{0}^{4} (6 x^{3} - 3 x) d x

360

Solution steps

\int_{0}^{4} 6 x^{3} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 6 x^{3} d x - \int_{0}^{4} 3 x d x

\int_{0}^{4} 6 x^{3} d x = 384

\int_{0}^{4} 3 x d x = 24

= 384 - 24

Simplify

= 360

\int_{1}^{2} 5^{4 x} d x

\int_{5}^{9} \frac{1}{x - 4} d x

\int_{0}^{y} cos (\frac{x}{y}) d z

\int_{0}^{1} \frac{1}{1 + x ^{3}} d x

\int_{0}^{1} \frac{x ^{2}}{3} d x

What is the integral from 0 to 4 of (6x^3-3x) ?
The integral from 0 to 4 of (6x^3-3x) is 360