What is the integral from 0 to 1 of e^u ?

The integral from 0 to 1 of e^u is e-1

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integral from 0 to 1 of e^u

\int_{0}^{1} e^{u} d u

e - 1

Solution steps

\int_{0}^{1} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= [e^{u}]_{0}^{1}

Compute the boundaries:

e - 1

= e - 1

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What is the integral from 0 to 1 of e^u ?
The integral from 0 to 1 of e^u is e-1