What is the integral from 0 to 1 of 6pix ?

The integral from 0 to 1 of 6pix is 3pi

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integral from 0 to 1 of 6pix

\int_{0}^{1} 6 π x d x

3 π

Solution steps

\int_{0}^{1} 6 π x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 π \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= 6 π [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 6 π \frac{1}{2}

Simplify

= 3 π

\int_{0}^{\infty} e^{- 3 t} d t

\int_{0}^{2} \frac{1}{ln ( x )} d x

\int_{0}^{l n (3)} 6 e^{3 x} d x

\int_{e}^{e^{2}} x ln (x) d x

\int_{0}^{1} - 2 x + 2 d x

What is the integral from 0 to 1 of 6pix ?
The integral from 0 to 1 of 6pix is 3pi