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Popular >

integral from 0 to 1 of-2x+2

Solution

\int_{0}^{1} - 2 x + 2 d x

Solution

1

Solution steps

\int_{0}^{1} - 2 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} 2 x d x + \int_{0}^{1} 2 d x

\int_{0}^{1} 2 x d x = 1

\int_{0}^{1} 2 d x = 2

= - 1 + 2

Simplify

= 1

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\int_{1}^{3} 2 x - 1 d x

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\int_{0}^{3} ∣ 3 x - 8 ∣ d x

integral from 2x to x^2 of cos(t)sin(t)

\int_{2 x}^{x^{2}} cos (t) sin (t) d t

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of-2x+2 ?
The integral from 0 to 1 of-2x+2 is 1