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Popular >

integral from-1 to 2 of |1-x|

Solution

\int_{- 1}^{2} ∣ 1 - x ∣ d x

Solution

\frac{5}{2}

+1

Decimal Notation

2.5

Solution steps

\int_{- 1}^{2} ∣ 1 - x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{1} 1 - x d x + \int_{1}^{2} - 1 + x d x

\int_{- 1}^{1} 1 - x d x = 2

\int_{1}^{2} - 1 + x d x = \frac{1}{2}

= 2 + \frac{1}{2}

Simplify

2 + \frac{1}{2} : \frac{5}{2}

= \frac{5}{2}

Popular Examples

integral from 0 to pi of 4cos^2(x)

\int_{0}^{π} 4 cos^{2} (x) d x

integral from-1 to 0 of x^{1/3}-x

\int_{- 1}^{0} x^{\frac{1}{3}} - x d x

integral from 0 to t of sin^2(x)

\int_{0}^{t} sin^{2} (x) d x

integral from-6 to 6 of x^2

\int_{- 6}^{6} x^{2} d x

integral from 0 to t of (sin(t))/t

\int_{0}^{t} \frac{sin ( t )}{t} d t

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of |1-x| ?
The integral from-1 to 2 of |1-x| is 5/2