What is the integral from 0 to log_{5 of (7)}5^x ?

The integral from 0 to log_{5 of (7)}5^x is 6/(ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to log_{5 of (7)}5^x

\int_{0}^{l o g_{5} (7)} 5^{x} d x

\frac{6}{ln ( 5 )}

Decimal Notation

3.72800 \dots

Solution steps

\int_{0}^{l o g_{5} (7)} 5^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{5 ^{x}}{ln ( 5 )}]_{0}^{l o g_{5} (7)}

Compute the boundaries:

\frac{6}{ln ( 5 )}

= \frac{6}{ln ( 5 )}

\int_{6 x}^{- 8} sin (t^{2}) d t

\int_{1}^{e} \frac{( 2 + ln ( x ) ) ^{3}}{x} d x

\int_{- 1}^{0} (- x - 1) d x

\int_{1}^{e^{x}} \frac{1}{t} d t

\int_{0}^{\frac{x}{n}} n (1 - x)^{n - 1} d x

What is the integral from 0 to log_{5 of (7)}5^x ?
The integral from 0 to log_{5 of (7)}5^x is 6/(ln(5))