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Popular >

integral from-1 to 2 of x+1

Solution

\int_{- 1}^{2} x + 1 d x

Solution

\frac{9}{2}

+1

Solution steps

\int_{- 1}^{2} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x d x + \int_{- 1}^{2} 1 d x

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 1 d x = 3

= \frac{3}{2} + 3

Simplify

\frac{3}{2} + 3 : \frac{9}{2}

= \frac{9}{2}

Popular Examples

integral from 0 to 2 of 2xe^x

\int_{0}^{2} 2 x e^{x} d x

integral from 1 to x of x^4

\int_{1}^{x} x^{4} d x

integral from 6 to 9 of 1/(x^2)

\int_{6}^{9} \frac{1}{x ^{2}} d x

integral from 1 to 3 of 2x^2-3x+5

\int_{1}^{3} 2 x^{2} - 3 x + 5 d x

integral from-1 to 1 of cos(2x)

\int_{- 1}^{1} cos (2 x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of x+1 ?
The integral from-1 to 2 of x+1 is 9/2