What is the integral from 0 to 5 of sin(x) ?

The integral from 0 to 5 of sin(x) is -cos(5)+1

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integral from 0 to 5 of sin(x)

\int_{0}^{5} sin (x) d x

- cos (5) + 1

Decimal

0.71633 \dots

Solution steps

\int_{0}^{5} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{5}

Compute the boundaries:

- cos (5) + 1

= - cos (5) + 1

\int_{27}^{216} 3 x d x

\int_{0}^{6} (12 x - 72) d x

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\int_{1}^{2} x^{- 5} d x

\int_{4}^{5} \frac{x}{2 x - 6} d x

What is the integral from 0 to 5 of sin(x) ?
The integral from 0 to 5 of sin(x) is -cos(5)+1