What is the integral from 27 to 216 of \sqrt[3]{x} ?

The integral from 27 to 216 of \sqrt[3]{x} is 3645/4

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integral from 27 to 216 of \sqrt[3]{x}

\int_{27}^{216} 3 x d x

\frac{3645}{4}

Decimal

911.25

Solution steps

\int_{27}^{216} 3 x d x

Apply the Power Rule

= [\frac{3}{4} x^{\frac{4}{3}}]_{27}^{216}

Compute the boundaries:

\frac{3645}{4}

= \frac{3645}{4}

\int_{0}^{6} (12 x - 72) d x

\int_{1}^{2} x^{- 5} d x

\int_{4}^{5} \frac{x}{2 x - 6} d x

\int_{0}^{1} 5 x^{4} + 3 x^{2} + 1 d x

\int_{7}^{8} \frac{1}{x} d x

What is the integral from 27 to 216 of \sqrt[3]{x} ?
The integral from 27 to 216 of \sqrt[3]{x} is 3645/4