What is the integral from 3 to 8 of sqrt(x+1) ?

The integral from 3 to 8 of sqrt(x+1) is 38/3

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integral from 3 to 8 of sqrt(x+1)

\int_{3}^{8} x + 1 d x

\frac{38}{3}

Decimal Notation

12.66666 \dots

Solution steps

\int_{3}^{8} x + 1 d x

Apply u-substitution

: \int_{4}^{9} u d u

= \int_{4}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

= [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= \frac{38}{3}

\int_{- \frac{3 π}{4}}^{0} sin (x) d x

\int_{3}^{- 3} 9 - x^{2} d x

\int_{- 3}^{- 1} \frac{1}{x ^{2}} d x

\int_{0}^{4} y 9 + y^{2} d y

\int_{0}^{1} (x^{\frac{4}{3}} - 2 x^{\frac{1}{3}}) d x

What is the integral from 3 to 8 of sqrt(x+1) ?
The integral from 3 to 8 of sqrt(x+1) is 38/3