What is the integral from-pi/2 to pi/2 of (-cos(x)) ?

The integral from-pi/2 to pi/2 of (-cos(x)) is -2

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integral from-pi/2 to pi/2 of (-cos(x))

\int_{- \frac{π}{2}}^{\frac{π}{2}} (- cos (x)) d x

- 2

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- \frac{π}{2}}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{- \frac{π}{2}}^{\frac{π}{2}}

Compute the boundaries:

2

= - 2

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\int_{0}^{5} - x^{2} + 9 d x

\int_{0}^{b} \frac{1}{32} v e^{- \frac{v ^{2}}{64}} d v

What is the integral from-pi/2 to pi/2 of (-cos(x)) ?
The integral from-pi/2 to pi/2 of (-cos(x)) is -2