What is the integral from 1 to 5 of (18(ln(x))^5)/x ?

The integral from 1 to 5 of (18(ln(x))^5)/x is 3ln^6(5)

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integral from 1 to 5 of (18(ln(x))^5)/x

\int_{1}^{5} \frac{18 ( ln ( x ) ) ^{5}}{x} d x

3 ln^{6} (5)

Decimal Notation

52.13947 \dots

Solution steps

\int_{1}^{5} \frac{18 ( ln ( x ) ) ^{5}}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int_{1}^{5} \frac{( ln ( x ) ) ^{5}}{x} d x

Apply u-substitution

: \int_{0}^{l n (5)} u^{5} d u

= 18 \cdot \int_{0}^{l n (5)} u^{5} d u

Apply the Power Rule

: [\frac{u ^{6}}{6}]_{0}^{l n (5)}

= 18 [\frac{u ^{6}}{6}]_{0}^{l n (5)}

Compute the boundaries:

\frac{ln ^{6} ( 5 )}{6}

= 18 \cdot \frac{ln ^{6} ( 5 )}{6}

Simplify

= 3 ln^{6} (5)

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What is the integral from 1 to 5 of (18(ln(x))^5)/x ?
The integral from 1 to 5 of (18(ln(x))^5)/x is 3ln^6(5)