What is the integral from pi to 2pi of (sin(x))/x ?

The integral from pi to 2pi of (sin(x))/x is \Si(2pi)-\Si(pi)

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integral from pi to 2pi of (sin(x))/x

\int_{π}^{2 π} \frac{sin ( x )}{x} d x

Si (2 π) - Si (π)

Solution steps

\int_{π}^{2 π} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{π}^{2 π}

Compute the boundaries:

Si (2 π) - Si (π)

= Si (2 π) - Si (π)

\int_{0}^{y} (y) d y

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\int_{0}^{e} \frac{ln ( x )}{x} d x

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\int_{- \frac{π}{4}}^{\frac{π}{4}} x^{4} tan (x) d x

What is the integral from pi to 2pi of (sin(x))/x ?
The integral from pi to 2pi of (sin(x))/x is \Si(2pi)-\Si(pi)