What is the integral from 0 to y of (y) ?

The integral from 0 to y of (y) is (y^2)/2

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integral from 0 to y of (y)

\int_{0}^{y} (y) d y

\frac{y ^{2}}{2}

Solution steps

\int_{0}^{y} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{y}

= [\frac{y ^{2}}{2}]_{0}^{y}

Compute the boundaries:

\frac{y ^{2}}{2}

= \frac{y ^{2}}{2}

\int_{2}^{4} \frac{x ^{2} - 9}{x - 3} d x

\int_{0}^{e} \frac{ln ( x )}{x} d x

\int_{2}^{1} x^{3} d x

\int_{- \frac{π}{4}}^{\frac{π}{4}} x^{4} tan (x) d x

\int_{e}^{e^{2}} \frac{1}{x} d x

What is the integral from 0 to y of (y) ?
The integral from 0 to y of (y) is (y^2)/2