What is the integral from 2 to 4 of 2/(x^2) ?

The integral from 2 to 4 of 2/(x^2) is 1/2

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integral from 2 to 4 of 2/(x^2)

\int_{2}^{4} \frac{2}{x ^{2}} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{2}^{4} \frac{2}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{2}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{4}

= 2 [- \frac{1}{x}]_{2}^{4}

Compute the boundaries:

\frac{1}{4}

= 2 \cdot \frac{1}{4}

Simplify

= \frac{1}{2}

\int_{1}^{4} 5 x + x d x

\int_{- \frac{π}{4}}^{\frac{π}{4}} (sec^{2} (x)) d x

\int_{0}^{1} e^{x^{3}} x^{2} d x

\int_{- 1}^{5} 2 x + 4 d x

\int_{0}^{1} x^{2} + x - 2 d x

What is the integral from 2 to 4 of 2/(x^2) ?
The integral from 2 to 4 of 2/(x^2) is 1/2