What is the integral from 1 to 2 of (x^2)^2 ?

The integral from 1 to 2 of (x^2)^2 is 31/5

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integral from 1 to 2 of (x^2)^2

\int_{1}^{2} (x^{2})^{2} d x

\frac{31}{5}

Decimal

6.2

Solution steps

\int_{1}^{2} (x^{2})^{2} d x

Simplify

(x^{2})^{2} : x^{4}

= \int_{1}^{2} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{1}^{2}

= [\frac{x ^{5}}{5}]_{1}^{2}

Compute the boundaries:

\frac{31}{5}

= \frac{31}{5}

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What is the integral from 1 to 2 of (x^2)^2 ?
The integral from 1 to 2 of (x^2)^2 is 31/5