What is the integral from-infinity to-3 of x/(4-x^2) ?

The integral from-infinity to-3 of x/(4-x^2) is diverges

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integral from-infinity to-3 of x/(4-x^2)

\int_{- \infty}^{- 3} \frac{x}{4 - x ^{2}} d x

diverges

Solution steps

\int_{- \infty}^{- 3} \frac{x}{4 - x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{4 - x ^{2}} d x = - \frac{1}{2} ln 4 - x^{2} + C

Compute the boundaries:

\int_{- \infty}^{- 3} \frac{x}{4 - x ^{2}} d x =

diverges

= diverges

\int_{0}^{4} 3 x^{3} d x

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\int_{- 4}^{3} (- x^{2} - 3 x) d x

\int_{0}^{1} x^{4} ln (x) d x

\int_{2}^{x} t^{3} d t

What is the integral from-infinity to-3 of x/(4-x^2) ?
The integral from-infinity to-3 of x/(4-x^2) is diverges