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Popular >

integral from 0 to 2 of-2t+2

Solution

\int_{0}^{2} - 2 t + 2 d t

Solution

0

Solution steps

\int_{0}^{2} - 2 t + 2 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} 2 t d t + \int_{0}^{2} 2 d t

\int_{0}^{2} 2 t d t = 4

\int_{0}^{2} 2 d t = 4

= - 4 + 4

Simplify

= 0

Popular Examples

integral from 0 to 2 of 8^x

\int_{0}^{2} 8^{x} d x

integral from 0 to 2 of (40)/(x^2+4)

\int_{0}^{2} \frac{40}{x ^{2} + 4} d x

integral from 9 to x^3 of 1/(p^2)

\int_{9}^{x^{3}} \frac{1}{p ^{2}} d p

integral from 0 to 4 of t^3

\int_{0}^{4} t^{3} d t

integral from-2 to 4 of (y+4)/2-(y^2)/4

\int_{- 2}^{4} \frac{y + 4}{2} - \frac{y ^{2}}{4} d y

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of-2t+2 ?
The integral from 0 to 2 of-2t+2 is 0