What is the integral from 0 to 1 of (sin(x)) ?

The integral from 0 to 1 of (sin(x)) is -cos(1)+1

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integral from 0 to 1 of (sin(x))

\int_{0}^{1} (sin (x)) d x

- cos (1) + 1

Decimal

0.45969 \dots

Solution steps

\int_{0}^{1} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{1}

Compute the boundaries:

- cos (1) + 1

= - cos (1) + 1

\int_{0}^{l n (x)} e^{y} d y

\int_{1}^{2} x 2^{x^{2}} d x

\int_{0}^{1} 2 + x^{\frac{1}{3}} d x

\int_{0}^{π} \frac{sin ( x )}{2} d x

\int_{2 π}^{3 π} x sin (x) d x

What is the integral from 0 to 1 of (sin(x)) ?
The integral from 0 to 1 of (sin(x)) is -cos(1)+1