What is the integral from 2 to 4 of (x^3-2)-ln(x+1) ?

The integral from 2 to 4 of (x^3-2)-ln(x+1) is 58+3ln(3)-5ln(5)

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integral from 2 to 4 of (x^3-2)-ln(x+1)

\int_{2}^{4} (x^{3} - 2) - ln (x + 1) d x

58 + 3 ln (3) - 5 ln (5)

Decimal Notation

53.24864 \dots

Solution steps

\int_{2}^{4} x^{3} - 2 - ln (x + 1) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} x^{3} d x - \int_{2}^{4} 2 d x - \int_{2}^{4} ln (x + 1) d x

\int_{2}^{4} x^{3} d x = 60

\int_{2}^{4} 2 d x = 4

\int_{2}^{4} ln (x + 1) d x = 5 ln (5) - 2 - 3 ln (3)

= 60 - 4 - (5 ln (5) - 2 - 3 ln (3))

Simplify

= 58 + 3 ln (3) - 5 ln (5)

\int_{- 2}^{- 1} \frac{1}{x ^{3}} + \frac{x ^{3}}{4} d x

\int_{3}^{4} (2 x - 5)^{4} d x

\int_{0}^{6} 3 x + 7 d x

\int_{0}^{1} (p) d p

\int_{- π}^{0} 2 x d x

What is the integral from 2 to 4 of (x^3-2)-ln(x+1) ?
The integral from 2 to 4 of (x^3-2)-ln(x+1) is 58+3ln(3)-5ln(5)