What is the integral from 0 to 1 of (p) ?

The integral from 0 to 1 of (p) is 1/2

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integral from 0 to 1 of (p)

\int_{0}^{1} (p) d p

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{0}^{1} p d p

Apply the Power Rule

: [\frac{p ^{2}}{2}]_{0}^{1}

= [\frac{p ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int_{- π}^{0} 2 x d x

\int_{- 1}^{0} 1 - 3 x d x

\int_{- 1}^{0} x^{2} (x + 1)^{\frac{1}{2}} d x

\int_{- π}^{0} x^{2} cos (n x) d x

\int_{0}^{1} g (x) d x

What is the integral from 0 to 1 of (p) ?
The integral from 0 to 1 of (p) is 1/2