What is the integral from 1 to 5 of e^{x^2} ?

The integral from 1 to 5 of e^{x^2} is (sqrt(pi)\erfi(5)-sqrt(pi)\erfi(1))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of e^{x^2}

\int_{1}^{5} e^{x^{2}} d x

\frac{π erfi ( 5 ) - π erfi ( 1 )}{2}

Solution steps

\int_{1}^{5} e^{x^{2}} d x

Use the nonelementary integral:

\int e^{x^{2}} d x = \frac{π}{2} erfi (x)

= [\frac{π}{2} erfi (x)]_{1}^{5}

Compute the boundaries:

\frac{π erfi ( 5 ) - π erfi ( 1 )}{2}

= \frac{π erfi ( 5 ) - π erfi ( 1 )}{2}

\int_{5}^{8} (\frac{3}{x ^{2}} - 1) d x

\int_{0}^{2} 2 t d t

\int_{0}^{π} (7 e^{x} + 8 sin (x)) d x

\int_{1}^{2} \frac{3 x ^{2}}{8} d x

\int_{0}^{3} (x e^{x}) d x

What is the integral from 1 to 5 of e^{x^2} ?
The integral from 1 to 5 of e^{x^2} is (sqrt(pi)\erfi(5)-sqrt(pi)\erfi(1))/2