What is the integral from 0 to pi of (7e^x+8sin(x)) ?

The integral from 0 to pi of (7e^x+8sin(x)) is 7e^pi+9

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integral from 0 to pi of (7e^x+8sin(x))

\int_{0}^{π} (7 e^{x} + 8 sin (x)) d x

7 e^{π} + 9

Decimal

170.98484 \dots

Solution steps

\int_{0}^{π} 7 e^{x} + 8 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 7 e^{x} d x + \int_{0}^{π} 8 sin (x) d x

\int_{0}^{π} 7 e^{x} d x = 7 (e^{π} - 1)

\int_{0}^{π} 8 sin (x) d x = 16

= 7 (e^{π} - 1) + 16

Simplify

7 (e^{π} - 1) + 16 : 7 e^{π} + 9

= 7 e^{π} + 9

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What is the integral from 0 to pi of (7e^x+8sin(x)) ?
The integral from 0 to pi of (7e^x+8sin(x)) is 7e^pi+9