What is the integral from-2 to x of (22t^2-21t) ?

The integral from-2 to x of (22t^2-21t) is (22(x^3+8))/3-21((x^2)/2-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to x of (22t^2-21t)

\int_{- 2}^{x} (22 t^{2} - 21 t) d t

\frac{22 ( x ^{3} + 8 )}{3} - 21 (\frac{x ^{2}}{2} - 2)

Solution steps

\int_{- 2}^{x} 22 t^{2} - 21 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{x} 22 t^{2} d t - \int_{- 2}^{x} 21 t d t

\int_{- 2}^{x} 22 t^{2} d t = \frac{22 ( x ^{3} + 8 )}{3}

\int_{- 2}^{x} 21 t d t = 21 (\frac{x ^{2}}{2} - 2)

= \frac{22 ( x ^{3} + 8 )}{3} - 21 (\frac{x ^{2}}{2} - 2)

\int_{1}^{5} - \frac{5}{x ^{2}} d x

\int_{0}^{0.05} 250 x d x

\int_{- 4}^{12} x + 4 d x

\int_{- 1}^{0} x^{\frac{1}{5}} - x d x

\int_{- 4}^{1} 1 d x

What is the integral from-2 to x of (22t^2-21t) ?
The integral from-2 to x of (22t^2-21t) is (22(x^3+8))/3-21((x^2)/2-2)