What is the integral from 0 to l of cos((npix)/l) ?

The integral from 0 to l of cos((npix)/l) is 0

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integral from 0 to l of cos((npix)/l)

\int_{0}^{l} cos (\frac{nπ x}{l}) d x

0

Solution steps

\int_{0}^{l} cos (\frac{nπ x}{l}) d x

Apply u-substitution

: \int_{0}^{nπ l} \frac{cos ( \frac{u}{l} )}{πn} d u

= \int_{0}^{nπ l} \frac{cos ( \frac{u}{l} )}{πn} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{πn} \cdot \int_{0}^{nπ l} cos (\frac{u}{l}) d u

Apply u-substitution

: \int_{0}^{πn} cos (v) l d v

= \frac{1}{πn} \cdot \int_{0}^{πn} cos (v) l d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{πn} l \cdot \int_{0}^{πn} cos (v) d v

Use the common integral:

\int cos (v) d v = sin (v)

= \frac{1}{πn} l [sin (v)]_{0}^{πn}

Compute the boundaries:

0

= \frac{1}{πn} l \cdot 0

Simplify

= 0

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What is the integral from 0 to l of cos((npix)/l) ?
The integral from 0 to l of cos((npix)/l) is 0