What is the integral from pi/2 to 0 of (cos(θ)) ?

The integral from pi/2 to 0 of (cos(θ)) is -1

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integral from pi/2 to 0 of (cos(θ))

\int_{\frac{π}{2}}^{0} (cos (θ)) d θ

- 1

Solution steps

\int_{\frac{π}{2}}^{0} cos (θ) d θ

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{\frac{π}{2}} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= - [sin (θ)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= - 1

\int_{- 2}^{2} (t^{2} - 4) d t

\int_{1}^{3} (x - 2)^{3} d x

\int_{0}^{\infty} e^{- y x} d x

\int_{0}^{2} x (2) d x

\int_{2}^{4} (2 x + 4)^{4} d x

What is the integral from pi/2 to 0 of (cos(θ)) ?
The integral from pi/2 to 0 of (cos(θ)) is -1