What is the tangent of f(x)=3x-2x^{-1/2}+1,\at x=1 ?

The tangent of f(x)=3x-2x^{-1/2}+1,\at x=1 is y=4x-2

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tangent of f(x)=3x-2x^{-1/2}+1,\at x=1

tangent of

f (x) = 3 x - 2 x^{- \frac{1}{2}} + 1, at x = 1

y = 4 x - 2

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

f (x) = 3 x - 2 x^{- \frac{1}{2}} + 1 : \frac{df ( x )}{d x} = \frac{1}{x ^{\frac{3}{2}}} + 3

Compute the slope of

f (x) = 3 x - 2 x^{- \frac{1}{2}} + 1

x = 1 : m = 4

Find the line with slope m=

4

and passing through

(1, 2) : y = 4 x - 2

y = 4 x - 2

10 y^{^{''}} + 1000 y = 20 cos (8 t), y (0) = 0, y^{^{'}} (0) = 0

y = 3 x - 2

y^{^{''}} + 6 y^{^{'}} + 34 y = 0

x \to 0 lim (\frac{5 x ^{3}}{x})

\frac{1}{4} x^{2}, 2 x^{2}, x - 3

What is the tangent of f(x)=3x-2x^{-1/2}+1,\at x=1 ?
The tangent of f(x)=3x-2x^{-1/2}+1,\at x=1 is y=4x-2