What is the integral from 0 to infinity of e^{5x} ?

The integral from 0 to infinity of e^{5x} is diverges

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integral from 0 to infinity of e^{5x}

\int_{0}^{\infty} e^{5 x} d x

diverges

Solution steps

\int_{0}^{\infty} e^{5 x} d x

Compute the indefinite integral:

\int e^{5 x} d x = \frac{1}{5} e^{5 x} + C

Compute the boundaries:

\int_{0}^{\infty} e^{5 x} d x =

diverges

= diverges

\int_{1}^{3} (2 - x) e^{x} d x

\int_{0}^{1} x^{\frac{1}{5}} - x d x

\int_{0}^{1} x 45 x^{2} + 36 d x

\int_{0}^{\frac{4}{5}} \frac{1}{25 x ^{2} + 16} d x

\int_{0}^{2} \frac{1}{( x + 4 ) ^{3}} d x

What is the integral from 0 to infinity of e^{5x} ?
The integral from 0 to infinity of e^{5x} is diverges