What is the tangent of f(x)= 7/(x+8),(5, 7/13) ?

The tangent of f(x)= 7/(x+8),(5, 7/13) is y=-7/169 x+126/169

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tangent of f(x)= 7/(x+8),(5, 7/13)

tangent of

f (x) = \frac{7}{x + 8}, (5, \frac{7}{13})

y = - \frac{7}{169} x + \frac{126}{169}

Solution steps

Find the slope of

f (x) = \frac{7}{x + 8} : \frac{df ( x )}{d x} = - \frac{7}{( x + 8 ) ^{2}}

Compute the slope of

f (x) = \frac{7}{x + 8}

(5, \frac{7}{13}) : m = - \frac{7}{169}

Find the line with slope m=

- \frac{7}{169}

and passing through

(5, \frac{7}{13}) : y = - \frac{7}{169} x + \frac{126}{169}

y = - \frac{7}{169} x + \frac{126}{169}

y^{^{'}} = 0.06 (y - 65)

n = 1 \sum \infty \frac{n}{2 n + 1}

\frac{d}{d x} (e^{x} + e^{- 3 x})

\frac{2 \cdot d y}{d x} + 100 \cdot y = 30 \cdot sin (60 x), y (0) = 0

\frac{d}{d x} (sin (2 x) + 3 cos (2 x))

What is the tangent of f(x)= 7/(x+8),(5, 7/13) ?
The tangent of f(x)= 7/(x+8),(5, 7/13) is y=-7/169 x+126/169