What is the sum from n=1 to infinity of n/(2n+1) ?

The sum from n=1 to infinity of n/(2n+1) is diverges

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sum from n=1 to infinity of n/(2n+1)

n = 1 \sum \infty \frac{n}{2 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n}{2 n + 1}

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (e^{x} + e^{- 3 x})

\frac{2 \cdot d y}{d x} + 100 \cdot y = 30 \cdot sin (60 x), y (0) = 0

\frac{d}{d x} (sin (2 x) + 3 cos (2 x))

8 x y^{^{'}} = 2 x e^{x} - 8 y + 6 x^{2}

h \to 0 lim (\frac{( - 5 + h ) - 25}{h})

What is the sum from n=1 to infinity of n/(2n+1) ?
The sum from n=1 to infinity of n/(2n+1) is diverges