What is the integral from 0 to 2 of e^{-t^2} ?

The integral from 0 to 2 of e^{-t^2} is 0.88208…

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integral from 0 to 2 of e^{-t^2}

\int_{0}^{2} e^{- t^{2}} d t

0.88208 \dots

Solution steps

\int_{0}^{2} e^{- t^{2}} d t

Use the nonelementary integral:

\int e^{- t^{2}} d t = \frac{π}{2} erf (t)

= [\frac{π}{2} erf (t)]_{0}^{2}

Compute the boundaries:

0.88208 \dots

= 0.88208 \dots

\int \frac{2 x + 1}{x ^{2} + x + 1} d x

x = - y - 5, x = 5 y - 11, y = 0

\int (sec^{2} (x) + 4) d x

\int \frac{( 1 - x )}{x} d x

\int (4 t^{2} + 3)^{2} d t

What is the integral from 0 to 2 of e^{-t^2} ?
The integral from 0 to 2 of e^{-t^2} is 0.88208…